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Annette [7]
4 years ago
5

Sharon is thinking about opening a bakery. She knows she wants to set her own hours, reduce her stress and make a profit. But sh

e still has a lot to think through. Which of the following would NOT be a good early step?
Computers and Technology
1 answer:
Harman [31]4 years ago
5 0
One choice that would be not a good step to make is to impulsively open the bakery without much thinking about all of the aspects involved in setting up a business. This could lead you to more loss of money. Hope this would help. Have a nice day.
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What is the term used to describe data sets are so large and complex that they become difficult to process using traditional dat
slega [8]

Answer:

Big Data

Explanation:

Big Data refers to data sets that are large, comprising of different varieties (structured and unstructured data types) and which cannot be processed by the day to day database management systems and computer software otherwise referred to as traditional software and techniques.

The term Big does not necessarily refer to a particular size that a dataset must attain but describes the nature of the dataset and the fact that traditional database management systems cannot be used to process them take for example

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2 years ago
Compare Fibonacci (recursion vs. bottom up)
ipn [44]

Answer:

C++ code explained below

Explanation:

#include<bits/stdc++.h>

#include <iostream>

using namespace std;

int FiboNR(int n)

{

int max=n+1;

int F[max];

F[0]=0;F[1]=1;

for(int i=2;i<=n;i++)

{

F[i]=F[i-1]+F[i-2];

}

return (F[n]);

}

int FiboR(int n)

{

if(n==0||n==1)

return n;

else

return (FiboR(n-1)+FiboR(n-2));

}

int main()

{

long long int i,f;

double t1,t2;

int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};

cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;

cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;

for(i=0;i<16;i++)

{

clock_t begin = clock();

f=FiboR(n[i]);

clock_t end = clock();

t1=double(end-begin); // elapsed time in milli secons

begin = clock();

f=FiboNR(n[i]);

end = clock();

t2=double(end-begin);

cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds

}

return 0;

}

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3 years ago
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sesenic [268]

Answer:

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