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Annette [7]
3 years ago
5

Sharon is thinking about opening a bakery. She knows she wants to set her own hours, reduce her stress and make a profit. But sh

e still has a lot to think through. Which of the following would NOT be a good early step?
Computers and Technology
1 answer:
Harman [31]3 years ago
5 0
One choice that would be not a good step to make is to impulsively open the bakery without much thinking about all of the aspects involved in setting up a business. This could lead you to more loss of money. Hope this would help. Have a nice day.
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3 years ago
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Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,
insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0
3 years ago
Assume the user types in 7 and 10. What is output by the following?
Marianna [84]

Answer:

Enter a number: 7

Enter a number: 10

Traceback (most recent call last):

 File "main.py", line 3, in <module>

   print (numi + num2)

NameError: name 'numi' is not defined

Explanation:

The typo in the print statement causes a run-time error, where obviously num1+num2 was expected, and an output of 17.

3 0
3 years ago
The while loop and the do loop are equivalent in their expressive power; in other words, you can rewrite a while loop using a do
sleet_krkn [62]
I think False...

I hope this helps
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Why might a peer-to-peer network not be the best choice for a large corporate office setting?
omeli [17]

Answer:

a it is less private

Explanation:

8 0
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