Answer:
Following are attached images that will help you understand the complete code. The code is tested with different variables and different outputs are obtained. All the necessary description is given in the form o comments inside the code.
Explanation:
Whatever you have written on the page is what it'll name it.
Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
Answer:
In the distributing computing, distributed object system is the process in which the distributed object are get distributed in different address space. The distributed object system is the enhancement of the client server model.
Distributed object are basically refers to the software module which are designed in such a way, so that they work together in the network.
And it is distributed physically within the network area and the methods is executed on the basis of remote host in the distributed system.
