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inysia [295]
3 years ago
5

A shipment of racquetballs with a mean diameter of 60 mm and a standard deviation of 0.9 mm is normally distributed. By how many

standard deviations does a racquetball with a diameter of 58.2 mm differ from the mean? (5 points)
a 0.9
b 1
c 2
d 3
please answer correctly this is for my exam
Mathematics
1 answer:
Gnesinka [82]3 years ago
4 0

Answer:

your answer should be(B) from my point of view

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A − 7 = 3 (b+2) pls answer soon
Alexeev081 [22]
I believe the answer is....

For solving for a

a-7= 3(b+2) ———> distribute 3(b+2)
a-7= 3b+6 ———-> add 7 on both sides

a-7= 3b+6
a+7= 3b +7 ———-> the 7’s cancel out so you’re left with....

a = 3b + 13 (That’s your answer)

Hope that helped :3
8 0
3 years ago
There are 35 people in a room. There are
Degger [83]

Answer:

Male=21 Female=14

Step-by-step explanation:

So the problem would be (f)+(f+7)=35

first you would subtract 7 from 35

Now you have (f)+(f)=28 or 2f=28

Then you divide both sides by two

f=14

and since we know there is 7 more males then the answer is

m=21

5 0
3 years ago
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Andrews [41]

Answer:

c

d

Step-by-step explanation:

4 0
3 years ago
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NemiM [27]

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=(3x−y)(x+y)

Answer:

(3x−y)(x+y)

5 0
3 years ago
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(√0,04-√(-1,2)²+√121)×√81
Semenov [28]

Answer:  90

Step-by-step explanation:

\displaystyle\ \Large \boldsymbol{} (\sqrt{0,04}-\sqrt{(-1,2)^2}+\sqrt{121 } ) \cdot \sqrt{81} = \\\\\\(0,2-1,2+11)\cdot 9=(11-1)\cdot 9=90

6 0
3 years ago
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