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2 years ago

Besides a histogram what are some other ways you can display these data

1 answer:

6 0

Pictograph, Bar Graph, Circle Graph, Line Graph, Stem-and-Leaf Plot, Box-and-Whisker Plot, Line Plot, and Scatter Plot. Hope this helps, I'm learning the same thing right now test tomorrow thanks for the practice!

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1. Solve the following proportion x/2 = 8/9

Ivanshal [37]

X/2=8/9 | *2
x=16/9≈ 1,78

2. 1 $.........1,09 Euro
x$...........157 Euro

x=157*1/1,09≈144,04 $

5 0

2 years ago

Find the root of 6x-48=0

Kisachek [45]

X=-8 final answer. hope that helps

3 0

2 years ago

Read 2 more answers

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

2 years ago

diagrams are not drawn to scale. do numbers 10 and 12. i only care about the answers & the steps to get the answers. pls don

Stella [2.4K]

10. from the question; the circle theorem obeyed is "angled formed by semi-circle"

The angle formed in a semicircle is 90 degrees, hence

$m\angle XYZ=90^{\circ}$

This gives

$m\angle YXZ\text{ + m}\angle YZX\text{ = 90}$

But

$\begin{gathered} m\angle YXZ\text{ = 2x + 8} \\ m\angle YZX\text{ = 5X - 2} \end{gathered}$

Substituting values we get

$\begin{gathered} 2x\text{ + 8 + 5x - 2 = 90} \\ 2x\text{ + 5x + 8 - 2 = 90} \\ 7x\text{ + 6 = 90} \\ 7x\text{ = 90 -6} \\ 7x\text{ = 84} \\ \text{divide both sides by 7} \\ x\text{ = }\frac{84}{7} \\ x\text{ = 12} \end{gathered}$

hence, x =12

3 0

5 months ago

Order them from least to greatest

ella [17]

8/3, 30/7, 40/9, 21/4

7 0

2 years ago

Read 2 more answers