Answer:
I think the total number of combinations of 3 from 6 = 6C3 = 20
All possible combinations of 3 which have a product divisible by 3 must contain either a 3 or a 6.
So the number not divisible must be 3 combinations from the number 1, 2, 4, and 5.= which is 4
So the required probability is 20-4 ? 20 = 16/20 = 0.8 Answer
Hope this help you! :)
Answer:
14x-11y
Step-by-step explanation:
6x-2y-5=5-9y+8x
eliminate opposites
6x-2y-9y+8x
collect like terms
14x-11y
14$ i think and good luck on ur test
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