Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
1. To translate to the left, add to x.
The equation is: y = |x + 2|
2. To translate down, add to y.
The equation is: y + 2 = |x| OR y = |x| - 2 (subtract 2 from each side)
Hope this helps!
Answer:
A
Step-by-step explanation:
The x-intercepts are the roots of a parabola. Specifically, when a parabola is in the form
, where h and k are real numbers, the roots are
and
.
Our parabola has a plus, though. That's a problem, right?
No!
, so there's no problem. So, our roots are
and
.
So, the answer is A and we're done!
Answer:
shrek or 43jaqhfh3hyuy8
Step-by-step explanation: