All categories

3 years ago

Hi, can someone please answer this questions, THANKS

Mathematics

1 answer:

aliya0001 [1]3 years ago

3 0

Answer:

supplementary angles add up to 180 degrees and complementary add up to 90 degrees

Step-by-step explanation:

You might be interested in

On a map, 1 inch equals 25 miles.Two cities are 3 inches apart on the map.What is the actual distance between the cities?

SVEN [57.7K]

Answer:

75 miles

Step-by-step explanation:

We are given the scale on the map, which is that 1 inch is 25 miles in real life. We can write that as a ratio of 1 inch: 25 miles. Now say we have two inches, then we have 50 miles because we add on another 25 miles, then we do that again and we get to 75 miles.

Another way to think about it (more complicated):

you can represent ratios as a fraction

so we do 1/25=3/x

To find x, we can do (25*3)/1 which equals 75, if you don't know what I did there then you don't know, sorry!

you can also do it in a different way

same scenario though

you represent it as a fraction

and do 1/25=3/x. We see that the ratio from 1 to 3 is multiplied by 3 so that means the ratio from 25 to x is also going to be multiplied by 3, and 25 multiplied by 3 is 75.

Please let me know if you have any questions.

5 0

3 years ago

Read 2 more answers

Which of the following could be used to calculate the area of a sector in the circle shown below

lara [203]

Answer:

Therefore the Last option is correct

$\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})$

Step-by-step explanation:

Given:

Radius = r = 8 in

θ = 42°

To Find:

Area of Sector = ?

Solution:

We know that

$\textrm{Area of Sector}=\pi (Radius)^{2}\times \frac{\theta}{360}$

Substituting the given values in the formula we get

$\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})$

Which is the required Answer.

Therefore the Last option is correct

$\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})$

8 0

3 years ago

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$