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gogolik [260]
3 years ago
7

Round 33127 to the nearest hundred

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0
33000? Or 32000 either one aHHH
Svetlanka [38]3 years ago
6 0
33,000 should be the correct answer

33,127, round it to the nearest hundred

1 is less than 5 therefore it will go down

33,000 should be the correct answer
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A new operation is defined by a△b=a^2-b/b-a^2. 4△3.
dmitriy555 [2]

As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1

As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.

Given, a△b=a^2-b/b-a^2

now 4△3 = (4^2-3) / (3-4^2)  

4△3 = (16-3) / (3-16)        

4△3 = 13 / -13  

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Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.

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1 year ago
Find the equation of quadratic function determined from the graph below?
Aleksandr [31]

Step-by-step explanation:

The x-intercepts are x = -1 and x = 5, so:

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The vertex is (2, -3), so:

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Simplifying:

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3 0
4 years ago
Suppose we want to choose a value of x within 3 units of 11. [This means a value of x that is less than 3 units away from 11.] T
Dahasolnce [82]

Answer:

(a) [8, 14]

(b)  8 \leq x \leq 14

(c)See attachment

Step-by-step explanation:

We want to choose a value of x within 3 units of 11.

(a)Now, 11-3=8 and 11+3=14

The possible values of x ranges is in the closed interval [8,14]

(b) Since x is within 3 units of 11., we have:

|11-x|\leq3

Solving the absolute inequality

-3 \leq 11-x \leq 3\\$In $ -3 \leq 11-x\\ x \leq 11+3\\x \leq 14\\\\$In $ 11-x \leq 3\\ 11-3 \leq x\\8 \leq x\\$Therefore,an inequality that represents all values of x that meet this constraint is:$\\8 \leq x \leq 14

(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.

5 0
3 years ago
Read 2 more answers
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