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gogolik [260]
3 years ago
7

Round 33127 to the nearest hundred

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0
33000? Or 32000 either one aHHH
Svetlanka [38]3 years ago
6 0
33,000 should be the correct answer

33,127, round it to the nearest hundred

1 is less than 5 therefore it will go down

33,000 should be the correct answer
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Which figure shows a reflection of pre-image QRS over the line t?<br> (Picture has answers.)
Vika [28.1K]

A, because its reflecting off of the y axis

7 0
3 years ago
Read 2 more answers
In a survey of 2000 people, 50% of them visited the country A and 40% of them
denis23 [38]

Step-by-step explanation:

n (U)=2000

n (A)=50% of 2000

=(50÷100)×2000

= 1000

n( B) = 40%

= (40÷100)×2000

= 800

n(AuB)(compliment) = 15%

=(15÷100)×2000

=300

Venn diagram ta banauna aauxha holani

I hope you know how to make a Venn diagram.

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7 0
3 years ago
Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua
goblinko [34]
<h2>Hello!</h2>

The answer is:  There is a total of 5.797 gallons pumped during the given period.

<h2>Why?</h2>

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

D(t)=\frac{5t}{1+3t}

So, the integral will be:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dx

So, integrating we have:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx

Performing a change of variable, we have:

1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}

Then, substituting, we have:

\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du

\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )

\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du

\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]

Reverting the change of variable, we have:

\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]

Then, evaluating we have:

\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0
4 years ago
A toy that was originally $35 is now marked down to $28. What percentage was the toy marked down to
Mkey [24]

Answer: 20% off

Step-by-step explanation:

35.00 times .20 = 7.00

35.00 minus 7.00 = 28.00

4 0
3 years ago
Priya starts with $50 in her bank account. She then deposits $20 each week for 12 weeks.
liubo4ka [24]

Answer:

10 weeks

Step-by-step explanation:

20x+50=250

First subtract 50 from both sides, which gives you 20x=200

then divide 20 from both sides which gives you x=10

3 0
3 years ago
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