All categories

3 years ago

Please could you help with this question and explain how to find the answer??

Mathematics

1 answer:

mamaluj [8]3 years ago

5 0

Your only option is to fill in the given points. That will give you two equations from which you can work out k and a.

Fill in (1,7) gives the easy formula 7 = k·a
Fill in (3,175) gives 175 = k·a·a·a

If you replace k·a in the second one with 7, you get:

175 = 7·a·a => a²=25 => a=5

Fron this and the first eqn follows k=7/5

You might be interested in

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

85% confidence level

So $\alpha = 0.15$ , z is the value of Z that has a pvalue of $1 - \frac{0.15}{2} = 0.925$ , so $Z = 1.44$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with $M = 0.03, \pi = 0.21$

Then

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.44\sqrt{\frac{0.21*0.79}{n}}$

$0.03\sqrt{n} = 1.44\sqrt{0.21*0.79}$

$\sqrt{n} = \frac{1.44\sqrt{0.21*0.79}}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.44\sqrt{0.21*0.79}}{0.03})^{2}$

$n = 382.23$

Rounding up

We need a sample size of at least 383.

6 0

3 years ago

State the equation, in slope-intercept form of each of the following graph

11Alexandr11 [23.1K]

Answer:

A) y=(1/4)x-1, 4y=x-4

B) y=-2x

3 0

3 years ago

The sum of the squares of three consecutive integers is 50. Find the integers. (Hint: If one integer is x, the next consecutive

Agata [3.3K]

Answer:

There's two answers.

-5, -4, and -3

3, 4, 5

Step-by-step explanation:

$x^{2} +(x+1)^{2} +(x+2)^{2} =50\\x^{2} +x^{2} +2x+1+x^{2} +4x+4=50\\3x^{2} +6x+5=50\\3x^{2} +6x-45=0\\3(x^{2} +2x-15)=0\\(x+5)(x-3)=0\\x = -5\\x = 3\\$