Question

I'll mark as brainliest if it lets me;-;please answer B. & C. with solution:)​

Answer 1

Answer:

B. AC = 22, BC = 22, AB = 44

C. AC = 30, BC = 30, AB = 60

Step-by-step explanation:

B.

$radius \: \overline {OR} \perp chord \: \overline {AB}$ at C. (given)

$\therefore AC = BC$ (perpendicular dropped from the center of the circle to the chord bisects the chord)

$\therefore 2x - 6 = x + 8$

$\therefore 2x - x= 6 + 8$

$\therefore x= 14$

$AC = 2x-6=2(14)-6=28-6= 22$

$BC= x + 8=14 + 8= 22$

AB = AC + BC = 22 + 22 = 44

C.

$radius \: \overline {OR} \perp chord \: \overline {AB}$ at C. (given)

$\therefore BC = AC$ (perpendicular dropped from the center of the circle to the chord bisects the chord)

$\therefore 7x-5=4x+10$

$\therefore 7x - 4x= 5 + 10$

$\therefore 3x= 15$

$\therefore x= \frac{15}{3}$

$\therefore x= 5$

$AC = 4x+10=4(5)+10=20+10= 30$

$BC= 7x - 5=7(5)-5=35-5= 30$

AB = AC + BC = 30 + 30 = 60