All categories

3 years ago

Juan has already run 6 miles this month. He plans to run an additional 3 miles each day.

Mathematics

2 answers:

Ksivusya [100]3 years ago

7 0

Answer:

3x + 6 = 45

Step-by-step explanation:

mart [117]3 years ago

7 0

Answer: 14 days

Step-by-step explanation:

$2.5x +6 =41\\ -6 -6\\2.5x = 41\\\\\\2.5\\x=14$

You might be interested in

Working alone, Ryan can dig a 10 ft by 10 ft hole in 5 hours Castel can dig the same hole in 6 hours how long would it take them

Fed [463]

Answer:

The time taken by both boys to complete work = 2.73 hours

Step-by-step explanation:

Time taken by rayan to dig hole $T_{1}$ = 5 hours

Time taken by castel to dig hole $T_{2}$ = 6 hours

Now the time taken by both persons working together

$T = \frac{T_{1} T_{2} }{T_{1} + T_{2}}$

Put all the values in above formula we get

$T = \frac{ 30 }{6 + 5}$

$T = \frac{30}{11}$

T = 2.73 hours

Therefore the time taken by both boys to complete work = 2.73 hours

6 0

3 years ago

14 lessons costs $210. What would 72 lessons cost

Oksi-84 [34.3K]

Answer:

$1,080

Step-by-step explanation:

To solve, we can make a proportion

14 lessons are $210 and 72 lessons are $x

14/210=72/x

Cross multiply

14*x=210*72

14x=15120

To solve for x, we need to get x by itself. Since x is being multiplied by 14, divide both sides by 14.

14x/14=15120/14

x=1080

So, 72 lessons will cost $1,080

4 0

2 years ago

Read 2 more answers

write the equation of the line that passes through the given points (0,-1) and (-5,-7) Simplify your answer

USPshnik [31]

Answer:

y = 6/5 x-1 slope intercept form

6x-5y = 5 standard form

Step-by-step explanation:

We have the points (0,-1) and (-5,-7)

We can find the slope using

m = (y2-y1)/(x2-x1)

= (-7--1)/(-5-0)

= (-7+1)/(-5-0)

= -6/-5

= 6/5

We also have the y intercept ( when x=0) It is -1

We can use the slope intercept form of the equation y = mx+b

y = 6/5 x-1

Depending on what you mean when you say simplify your answer

We can put it in standard form ax+by = C

Multiply both sides by 5

5y =5* 6/5 x-1*5

5y = 6x-5

Subtract 6x from each side

-6x+5y = 6x-6x-5

-6x+5y = -5

Multiply by -1

6x-5y = 5

4 0

3 years ago

Hi anyone indian here??

densk [106]

Answer:

I'm not lol

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough

liberstina [14]

Answer:

a) $t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

$\bar X=1175$ represent the sample mean for the cubic feets of households

$\sigma=250$ represent the population standard deviation

$n=100$ sample size

$\mu_o =1425$ represent the value to verify

$\alpha=0.025$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1425$

Alternative hypothesis: $\mu < 1425$

Since we don't know the deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10$

The degrees of freedom are given by:

$df=n-1=100-1=99$

The p value for this case would be given by:

$p_v =P(t_{99}$

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with 99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

$t_{\alpha/2}=1.984$

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0

3 years ago