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dezoksy [38]
3 years ago
6

The perimeter of a rectangle is 230 feet. The length is 56 feet. What is the width?

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

w=59 feet

Step-by-step explanation:

Using the formula

P=2(l+w)

Solving for w

w=P/2﹣l = 230/2﹣56

= 59 feet

Hope this helps!

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Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
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\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

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\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

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