All categories

3 years ago

Please help! (Find the area of the shaded region)

Mathematics

1 answer:

jeyben [28]3 years ago

8 0

Answer:

9.43 ft

Step-by-step explanation:

First, we need to find the area of the entire circle(shaded & unshaded), which is 12.57, with a radius of 2 ft. Next, we find the area of the white area, and NOT the shaded area, which is 3.14, with a radius of 1 ft. Now, we need to subtract the white area(3.14) from the total area(12.57), which is 9.43.

Hope this helps!

You might be interested in

IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each

gizmo_the_mogwai [7]

Applying the congruent chords theorem, the value of x is: 7.

Length of segment LP is: 6 units.

<h3>What is a Chord in Geometry?</h3>

In geometry, a chord is defined as the line segment that joins two points on the circumference of a circle.

<h3>What is the Congruent Chords Theorem?</h3>

In a circle, if two chords are congruent, then they are equidistant from the center of a circle, according to the congruent chords theorem.

In the circle given, chords JK = LM = 12 units. This means both chords are congruent, therefore, they are equidistant from the center of the circle S.

According to the congruent chords theorem, NS = PS, thus:

8 = 2x - 6

8 + 6 = 2x

14 = 2x

Divide both sides by 2

14/2 = 2x/2

7 = x

x = 7

LP = 1/2(12)

LP = 6 units.

In summary, applying the congruent chords theorem, the value of x is: 7.

Length of segment LP is: 6 units.

Learn more about the congruent chords theorem on:

brainly.com/question/7511582

#SPJ1

4 0

2 years ago

In a newspaper, it was reported that the number of yearly robberies in Springfield in 2012 was 200, and then went down by 26% in

lapo4ka [179]

Answer:148

Step-by-step explanation:1% = 2 x 26 = 52 - 200 = 148

8 0

2 years ago

How do you simplify this?

lions [1.4K]

Answer:

sinA(cosA+sinA)*cosA

Step-by-step explanation:

(sinA(2cosA+sinA-cosA))/secA

sinA(cosA+sinA)/secA

sinA(cosA+sinA)*cosA

8 0

2 years ago

Which equation describes the relationship of the<br> graphs of f(x) and g(x)?

I am Lyosha [343]

Answer:

Depends on which function is which...

Step-by-step explanation:

The blue graph is the same as the yellow graph but raised up 1 unit. That means either:

blue function rule = yellow function rule + 1

yellow function rule = blue function rule - 1

Your picture doesn't say which function is <em>f</em> and which is <em>g</em>.

If, just to pick a possibility, the blue function is <em>g</em>(<em>x</em>), then

g(x) = f(x) + 1

If the blue function is <em>f</em>(<em>x</em>), then

g(x) = f(x) - 1

8 0

1 year ago

According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var

-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}$

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.9

11.2

11.5

11.8

n=10(even)

$Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7$

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}$

Standard deviation :0.89916

8.3

,10.3

,10.5

,10.6

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5$

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2$

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range : $(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)$

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0

2 years ago