Answer: The probability that the height of a randomly selected female college basketball player is between 69 and 71 inches is 0.24
Step-by-step explanation:
Since the heights of all female college basketball players produce a normal distribution, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = heights of all female college basketball players.
µ = mean height
σ = standard deviation
From the information given,
µ = 68 inches
σ = 2 inches
We want to find the probability that the height of a randomly selected female college basketball player is between 69 and 71 inches is expressed as
P(69 ≤ x ≤ 75)
For x = 69,
z = (69 - 68)/2 = 0.5
Looking at the normal distribution table, the probability corresponding to the z score is 0.6915
For x = 71,
z = (71 - 68)/2 = 1.5
Looking at the normal distribution table, the probability corresponding to the z score is 0.9332
Therefore,
P(69 ≤ x ≤ 75) = 0.9332 - 0.6915 = 0.24
Answer:
x = 5
Step-by-step explanation:
AB/BC = AD/DE
9/3 = 15/x
9x = 45
x = 5
Answer:
Step-by-step explanation:
Total Weight = 2½ + 1⅓ + 2
= 5/2 + 4/3 + 2
= 15/6 + 8/6 + 12/6
= 35/6
= 5⅚ pounds
x ≤ -4 will result in an imaginary number. (From the graph it's actually 3.5, so if you want to view in REAL number then it's x ≤ -3.5 which will result in imaginary numbers.)
But if you want an integer then It's x ≤ -4
Real Number as it's x ≤ -3.5
5x + 10x = 180
15x = 180
X = 12
5 x 12 = 60
10 x 12 = 120
The angles are 60° and 120°