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sweet-ann [11.9K]
3 years ago
7

Sabrina has gone to work the last 50 days. On 28 of those days, she arrived before 7:30 A.M. On the rest of the days, she arrive

d after 7:30 A.M. What is the experimental probability that she will arrive at work before 7:30 A.M. On her next day of work? What is the experimental probability that she will arrive after 7:30 A.M.?
Mathematics
1 answer:
AlexFokin [52]3 years ago
4 0

Answer:

Prob (Arrive before 7.30) =  14 / 25 ; Prob (Arrive after 7.30) = 11 / 25

Step-by-step explanation:

Prob (Arrive before 7.30) = No. of days before 7.30 arrival / Total work days

= 28 / 50  = 14 / 25

Prob (Arrive after 7.30) = No. of days after 7.30 arrival / Total work days

= (50 - 28) / 50 = 22 / 50 = 11 / 25

or , 1 - Prob (Arrive before 7.30) = 1 - 14/25 = (25 - 11) / 25 = 11/ 25

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1. The formula expressing the dependence of the variable s on t is: s = 60 - 12t

2. the distance travelled at time t = 3.5 h is 18 Km

<h3>What is speed? </h3>

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

<h3>1. How to determine the formula expressing the dependence of the variable s on t</h3>

From the question given, bicyclist traveled with a speed of 12 km/h from a camping ground to a station, located 60 km.

Thus, we shall determine the distance travel in time t as follow

  • Speed = 12 Km/h
  • Time = t
  • Distance in time t = ?

Speed = distance / time

12 = distance / t

Cross multiply

Distance = 12 × t

Distance in time t = 12t

But the total distance travelled is 60 Km. Thus, the remaining distance (s) from the bicyclist to the station at time (t) will be given as:

s = 60 - 12t

Thus, the formula expressing the dependence of the variable s on t is: s = 60 - 12t

<h3>2. How to determine the distance at t = 3.5 hours</h3>

The distance at t = 3.5 hours can be obtained as illustrated below:

  • Time (t) = 3.5 hours
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s = 60 - 12t

s = 60 - (12 × 3.5)

s = 60 - 42

s = 18 Km

Thus, the distance travelled at t = 3.5 hours is 18 km

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