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Elza [17]
2 years ago
15

Please help provide the product in standard form !!

Mathematics
1 answer:
astraxan [27]2 years ago
8 0

Answer:

x^3+4x^2+5x+2

Step-by-step explanation:

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You will not be given credit for your answer if you do not include your equation! Your family took a trip to Florida. After the
bazaltina [42]

Answer:

80 mph

Step-by-step explanation:

720÷9=80

hope this helps!!!

3 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
jorge, the shipping manager at Durable Products, writes a memo proposing that that they stop using RoadHog Trucking Company and
goblinko [34]

Answer:

If it is causing other accounts to grow also that means that they would be in competition.

Step-by-step explanation:

7 0
3 years ago
Trig help ...............
Flauer [41]
Letter D

A = 135°
B = 30°

cosAcosB - sinAsinB = cos(A+B)

cos(135°+30°)
cos(165°)
4 0
3 years ago
Read 2 more answers
Solve for x. mx2 + y e = b
m_a_m_a [10]
X=(b/2m)*y-e is the answer I believe.
7 0
3 years ago
Read 2 more answers
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