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3 years ago

PLEASE HELP ME IM MARKING ANSWER BRAINLIEST RIGHT NOW!!Mr. Youngbear buys T-shirts in boxes

Mathematics

1 answer:

Musya8 [376]3 years ago

3 0

Step-by-step explanation:

1. Ok so first we need to figure out how many boxes of shirts he bought. In each box there are 20 shirts and he sold 93. So if we round it, he bought about 100 T-shirts. 100 ÷ 20 = 5. So he bought 5 boxes of shirts.

2. Next we need to figure out how much he spent on the shirts. 5*80=400. So he spent $400 dollars on the shirts.

3. We need to find out the amount of money he made from selling the shirts. 6*93=558

4. We need to find the profit so you subtract the total expenses from the total revenue. 558-400= 158. So the profit is $158

Answer: Mr. Youngbear made 158 dollars worth of profit after selling 93 T-shirts.

(I dont know if this is correct, but I hope I was able to help!)

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9.3.2 Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Find the values of d

kotegsom [21]

Answer:

$\frac{}{d}$ = −0.26

$s_{d}$ = 0.4219

Step-by-step explanation:

Given:

Sample1: 98.1 98.8 97.3 97.5 97.9

Sample2: 98.7 99.4 97.7 97.1 98.0

Sample 1 Sample 2 Difference d

98.1 98.7 -0.6

98.8 99.4 -0.6

97.3 97.7 -0.4

97.5 97.1 0.4

97.9 98.0 -0.1

To find:

Find the values of $\frac{}{d}$ and $s_{d}$

d overbar ( $\frac{}{d}$ ) is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5

$\frac{}{d}$ = ∑d/n

= (−0.6 −0.6 −0.4 +0.4 −0.1) / 5

= −1.3 / 5

$\frac{}{d}$ = −0.26

s Subscript d is the sample standard deviation of the difference which is calculated as following:

$s_{d}$ = √∑( $d_{i}$ - $\frac{}{d}$ )²/ n-1

$s_{d}$ =

√ $(-0.6 - (-0.26))^{2} + (-0.6 - (-0.26))^{2} + (-0.4 - (-0.26))^{2} + (0.4-(-0.26))^{2} + (-0.1 - (-0.26))^{2} / 5-1$

= √ (−0.6 − (−0.26 ))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 −

(−0.26))² + (−0.1 − (−0.26))² / 5−1

= $\sqrt{\frac{0.1156 + 0.1156 + 0.0196 + 0.4356 + 0.0256}{4} }$

= $\sqrt{\frac{0.712}{4} }$

= $\sqrt{0.178}$

= 0.4219

$s_{d}$ = 0.4219

Subscript d represent

μ $_{d}$ represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.

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