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Damm [24]
3 years ago
11

kylie opened a bank account. she deposited 76.50 into her account every month for 10 months. she used 30.50 every month to pay f

or singing lessions after 10 months she used 1/4 of the total money left in her account to go to a talent camp what is the total amount of money kylie spent to go to talent camp?
Mathematics
1 answer:
topjm [15]3 years ago
5 0
The total amount of money Kylie spent to go to talent camp is 115. 

76.5 *10 =765 (Amount of money she deposited in 10 months)
30.5 *10 = 305 (Amount of money she used to pay for singing lessons in 10 months)
765 - 305 = 460 (Amount remaining after singing lessons for 10 months)
460/4 = 115 (Amount she used to go to a talent camp)
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Your computer supply store sells two types of inkjet printers. The first, type A, costs $269 and you make a $24 profit on each o
just olya [345]
This is the concept of applications of linear equations; suppose you need x number of type A and y number of type be to make the profits required;
Total number of printers will be:
x+y=120....i
Total amount made will be:
24x+18y=2340....ii
thus solving equations i and ii by substitution we shall have:
x+y=120
x=120-y
thus substituting the above in equation ii we get:
24(120-y)+18y=2340
2880-24y+18y=2340
putting like terms together we get
-24y+18y=2340-2880
540=6y
thus
y=540/2
y=90
hence;
x=120-90=30
Therefore to make the profit of $2340 you must sale 90 type A printers and 30 type B printers

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3 years ago
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Answer: A

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7 0
2 years ago
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LuckyWell [14K]
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Tyson began solving the system ​ {4x+2y=64x+5y=15 ​ by writing −3y=−9 .
Artyom0805 [142]
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5 0
3 years ago
A company maintains a large fleet of automobiles. To check the average number of miles driven per month, a random sample of 100
Bas_tet [7]

Answer:

df=n-1=100-1=99  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(99)}>2.7)=0.0082  

And since the p vaue is lower than the significance level we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

Data given

\bar X=2690 represent the sample mean

s=360 represent the sample standard deviation

n=100 sample size  

\mu_o =2600 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean of interest is different from 2600, the system of hypothesis would be:  

Null hypothesis:\mu = 2600  

Alternative hypothesis:\mu \neq 2600  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

The statistic for this case is given t_{calc}=2.7

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=100-1=99  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(99)}>2.7)=0.0082  

And since the p vaue is lower than the significance level we have enough evidence to reject the null hypothesis.

7 0
3 years ago
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