1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
3241004551 [841]
3 years ago
14

Can anyone help explain this math equation like I gotta turn this math in by midnight tonight!! I will give brainlist btw!!

Mathematics
1 answer:
ryzh [129]3 years ago
3 0

Answer: 1) 288 inch^3

2) 960 inch^3

3) 188 cm^3

4) 44 inch^3

5) 396 ft^3

6) 552 inch^3

Step-by-step explanation:

1) (2*3)(3*2)(2*4)=288 inch^3

2) (4*5)(4*3)(4*1)=960 inch^3

3) 4*4*8+3*4*5=188 cm^3

4) 2*2*8+2*6*1=44 in^3

5) 4*6*6+6*6*7=396 ft^3

6) 8*6*10+4*3*6=552 in^3

You might be interested in
Solve equation, check for extraneous solutions
fiasKO [112]

Start with

1=\dfrac{1}{n^2}+\dfrac{n^2-4n-5}{3n^2}

We observe that both fractions are not defined if n=0. So, we will assume n \neq 0.

We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}

We multiply both sides by 3n^2:

n^2-4n-2=3n^2

We move everything to one side and solve the quadratic equation:

2n^2+4n+2=0 \iff 2(n^2+2n+1)=0 \iff 2(n+1)^2=0 \iff n+1=0 \iff n=-1

We check the solution:

1=\dfrac{1}{1}+\dfrac{1+4-5}{3} \iff 1 = 1+0

which is true

8 0
3 years ago
What is the equation of the line with an x-intercept of -1 and a y-intercept of 2? y = 2x - 2 y = - 2x 2 y = 2x 2
guajiro [1.7K]
X intercept = -1,  y = 0           (-1, 0)

<span>y intercept = 2,  x = 0           (0, 2)
</span>
slope between (-1, 0) and (0, 2):

slope = (2 -0)/(0 - -1) =  2/1 = 2,           m = 2

Using point   (-1, 0)   x₁ = -1, y₁ = 0

y - y₁ = m(x - x₁)

y - 0 = 2*(x - -1)

y = 2(x + 1)

y = 2x + 2
6 0
3 years ago
Im in no rush just need help
Romashka [77]

Answer:

1. Right: pointing downwards

Left: pointing upwards

2. Right: pointing upwards

Left: pointing upwards

3. Right: pointing downwards

Left: pointing upwards

4a. True

4b. True

Step-by-step explanation:

When the leading coefficient is negative the equation will either open downwards or the y-values will decrease as the x-values increase. The opposite is true for when the leading coefficient is positive. When the degree is odd one end will point downwards while the other points upwards. When the degree is even, both ends point in the same direction.

I hope this helps :)

5 0
2 years ago
Which is the correct way to write three and one-tenth of a milliliter as an Arabic number?
Leya [2.2K]
     we have that
<span>three and one-tenth------> 3 1/10--------> (3*10+1)/10--------> 31/10-----> 3.1 

the answer is 3.1 ml</span>
4 0
3 years ago
What is the distance between -60 and -10 0n a number line?
JulsSmile [24]

Answer: 70

Step-by-step explanation: The absolute value of a number is its distance from zero on the number line. Since absolute value is a distance, it is always greater than or equal to zero.

5 0
3 years ago
Other questions:
  • PLEASE HELP!! 50 POINTS!!
    5·1 answer
  • What is the value of sin A for this triangle?
    6·2 answers
  • PLEASE HELP TIMED!!!!
    15·2 answers
  • Find the perimeter of a square if half of a diagonal is equal to 8 inches
    8·1 answer
  • How many full teaspoons should the child take of the prescribed 15mL of medication?
    10·1 answer
  • Fund the measure of angle 7. Measure if angle 7=2x+15 measure if angle 8 =3x
    14·1 answer
  • Determine two compatible numbers to use to estimate the quotient 5,071 divided by 62
    13·2 answers
  • Please help me
    12·1 answer
  • Aamir is five years younger than aslam four years later aslam will be twice as old as aamir find their present ages
    12·1 answer
  • write the written form of the following expressions given in the symbolic form, then simplify each expression.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!