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Sauron [17]
3 years ago
13

Factor the polynomial 12 – 161 + 63

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

  -(2)(43)

Step-by-step explanation:

Your "polynomial" is the constant 12 -161 +63 = -86. It has factors ...

  -86 = (-1)(2)(43)

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Paladinen [302]
<BOA = 360 -250 = 110
<<span>BDA = 110/2 = 55

<</span><span>BCA = 360 - (90+90+110)
</span><<span>BCA = 360 - 290
<</span><span>BCA = 70</span>
6 0
3 years ago
Select the solution(s) of the original equation. (x + 4)2 – 3(x + 4) – 3 = 0
zzz [600]

Answer:

x = ± √3 = ± 1.7321

x = 1

x = -1

Step-by-step explanation:

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6 0
3 years ago
a tight roll of paper, as delivered to the printer, is 60cm in diameter, and the paper is wound on to a wooden cylinder 8cm in d
Alekssandra [29.7K]

The area of the paper is the amount of space it occupies.

The length of papers around the edge is 1607680 cm

The given parameters are:

\mathbf{d_1 = 60cm}

\mathbf{d_2 = 60cm + 8cm = 68cm}

The area of the circle head is:

\mathbf{Area = \pi \frac{d^2}{4}}

So, we have:

\mathbf{Area = \pi \frac{d_2^2 - d_1^2}{4}}

Substitute known values

\mathbf{Area = \pi \frac{68^2 - 60^2}{4}}

\mathbf{Area = \pi \frac{1024}{4}}

\mathbf{Area = 256\pi}

The length of the paper is then calculated as:

\mathbf{Length = \frac{Area}{0.0005}}

This gives

\mathbf{Length = \frac{256\pi}{0.0005}}

\mathbf{Length = \frac{256 \times 3.14}{0.0005}}

\mathbf{Length = 1607680}

Hence, the length of papers around the edge is 1607680 cm

Read more about areas at:

brainly.com/question/2264643

4 0
2 years ago
Read 2 more answers
4(x-2+y) what is this for the distributive property​
DochEvi [55]

Answer:

4x + 4y - 8

Step-by-step explanation:

4(x - 2 +y) = 4*x -4*2 + 4*y by the distributive property

5 0
3 years ago
Suppose . has 4 critical points. List them in increasing lexographic order. By that we mean that (x, y) comes before (z, w) if o
V125BC [204]

The points are (0,0) Minimum and (1/6, 1/18) is the saddle point.

What is the saddle point?

  • A saddle point, also known as a minimax point, is a place on the surface of a function's graph where the slopes in orthogonal directions are all zero but the function does not have a local extremum.

To solve the question we have:

f(x,y) = xy(1-2x-6y)

Therefore, f(x,y) = xy-2x²y-6xy²

Finding the partial derivative of the above gives:

fₓ = y - 4xy-6y²

= x - 2x²-12xy

Therefore, when the above equations are set to 0 we get:

y - 4xy-6y² = 0.......(1)

x - 2x²-12xy  = 0......(2)

Dividing equations (1) and (2) by y and x respectively give:

1 - 4x - 6y = 0

1 - 2x - 12y = 0  

Solving gives:

x = 0.167 = 1/6

y = 0.056 = 1/18

When we place x in equation (1) we have:

y - 4(1/6)y-6y² = 0

y = 0 or y = 1/18

Similarly, x = 0 or 1/6

Therefore, the four critical points are:

(0,0) (1/6,1/18)

When x = 0 and y = 0

f(x,y) = 0 Hence this is a minimum

When x = 1/6 and y = 1/18

f (x,y) = 1/324 Which is a saddle point.

Therefore, the points are (0,0) Minimum, and (1/6, 1/18) is the saddle point.

Know more about saddle point here:

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The question you are looking for is here:

(1 point) The function f(x,y)=xy(1−2x−6y) has 4 critical points. List them and select the type of critical point. Points should be entered as ordered pairs and listed in increasing lexicographic order. By that, we mean that (x,y) comes before (z,w) if x

4 0
1 year ago
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