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Mathematics

1 answer:

astra-53 [7]3 years ago

4 0

Answer:

Stop wasting them

Step-by-step explanation:

Pls Mark me as brainliest

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Solve each equation for the given variable: 4x+6+3=17

Ede4ka [16]

$4x+6+3=17\\\\4x+9=17\ \ \ \ |subtract\ 9\ from\ both\ sides\\\\4x=8\ \ \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{\boxed{x=2}}$

8 0

4 years ago

Read 2 more answers

Solve for x. 0.9(5x+4) = 5.7 2.5X

Alenkinab [10]

Answer:

x=0.369231

Step-by-step explanation:

0.9(5x+4)=5.7(2.5x)

Step 1: Simplify both sides of the equation.

0.9(5x+4)=5.7(2.5x)

(0.9)(5x)+(0.9)(4)=5.7(2.5x)(Distribute)

4.5x+3.6=14.25x

Step 2: Subtract 14.25x from both sides.

4.5x+3.6−14.25x=14.25x−14.25x

−9.75x+3.6=0

Step 3: Subtract 3.6 from both sides.

−9.75x+3.6−3.6=0−3.6

−9.75x=−3.6

Step 4: Divide both sides by -9.75.

−9.75x/ −9.75 = −3.6/ −9.75

x=0.369231

7 0

4 years ago

3log5(x-10)-1/2log54=5log52 Solve each equation. #10

Inessa [10]

Answer:

$\large\boxed{x=14}$

Step-by-step explanation:

$3\log_5(x-10)-\dfrac{1}{2}\log_54=5\log_52\\\\\text{Domain:}\ x-10>0\to x>10\\\\\text{use}\\\\\log_ab^n=n\log_ab\\\\\log_ab-\log_ac=\log_a\left(\dfrac{b}{c}\right)\\========================\\\\\log_5(x-10)^3-\log_54^\frac{1}{2}=\log_52^5\qquad\text{use}\ a^\frac{1}{2}=\sqrt{a}\\\\\log_5(x-10)^3-\log_5\sqrt4=\log_532\\\\\log_5(x-10)^3-\log_52=\log_532\\\\\log_5\dfrac{(x-10)^3}{2}=\log_532\iff\dfrac{(x-10)^3}{2}=32\qquad\text{multiply both sides by 2}\\\\(x-10)^3=64\to x-10=\sqrt[3]{64}\\\\x-10=4\qquad\text{add 10 to both sides}\\\\x=14\in D$