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NARA [144]
2 years ago
13

The maintenance department at the main campus of a large state university receives daily requests to replace fluorescent light b

ulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 43 and a standard deviation of 11. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 10 and 43
Mathematics
1 answer:
Stella [2.4K]2 years ago
5 0

Answer:

The approximate percentage of lightbulb replacement requests numbering between 10 and 43 is of 49.85%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 43

Standard deviation = 11

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above the mean.

What is the approximate percentage of lightbulb replacement requests numbering between 10 and 43?

43 is the mean

10 = 43 - 3*11

So 10 is 3 standard deviations below the mean.

Of the 50% of measures below the mean, 99.7% are between 3 standard deviations below the mean(10) and the mean(43). So

0.5*0.997 = 0.4985.

0.4985*100% = 49.85%.

The approximate percentage of lightbulb replacement requests numbering between 10 and 43 is of 49.85%.

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Step-by-step explanation:

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For the given angle 0, identify the reference angle, _
ankoles [38]

Answer:

π\6

Step-by-step explanation:

The reference angle is the smallest angle measured from the terminal side of the angle (where the angle ends) to the x axis. The reference angle is an acute angle (i.e less than 90° or π/2)

For O = 11π/6 = 1.833π

1.833π is in the fourth quadrant between 3π/2 radians and 2π radians. Since it is in the fourth quadrant, the reference angle is given as:

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3 years ago
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2 years ago
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5 0
3 years ago
If (x, y) is a solution to the system of equations, what is the value of y? 1/4 x + 1/8 y = 2 1/3 x + 1/2 y = 4 A) 4 B) 6 C) -6
andre [41]
<h3>The value of y is 4</h3>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

\frac{1}{4}x + \frac{1}{8}y =2 ---------- eqn\ 1\\\\\frac{1}{3}x + \frac{1}{2}y = 4 -------------- eqn\ 2

We have to find value of y

From eqn 1,

\frac{1}{4}x + \frac{1}{8}y =2 \\\\2x + y = 2 \times 8\\\\2x + y = 16 ---- eqn\ 3

From eqn 2,

\frac{1}{3}x + \frac{1}{2}y = 4\\\\2x + 3y = 4 \times 6\\\\2x + 3y = 24 ------ eqn\ 4

Subtract eqn 3 from eqn 4

2x + 3y = 24

2x + y = 16

( - ) -----------------

2y = 8

y = 4

Thus value of y is 4

5 0
2 years ago
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