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Vesna [10]
3 years ago
8

Given that f(x) = −x + 4 and g(x) = −2x − 3, solve for f(g(x)) when x = 2.

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

Do g(2) first:  g(2) = -2*2 - 3 = -7

Put this into f:  f(g(2)) = -(-7) + 4 = 7 + 4 = 11

Step-by-step explanation:

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Step-by-step explanation:

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Explain step by step how to use the horizontal method the multiple the two polynomials
MatroZZZ [7]

Answer:

Step-by-step explanation:

Multiply each term of the first polynomial with   the second polynomial. Then combine the like terms.

(3a<em>² + 5a - 2)* (5a² -3a + 4)</em>

<em> = 3a² *(5a² -3a + 4)  + 5a*(5a² -3a + 4)  - 2*(5a² -3a + 4)</em>

<em>=3a²*5a² - 3a*3a² + 4*3a² +  5a*5a² - 3a*5a  + 4*5a + 5a²*(-2) - 3a*(-2) + 4*(-2)</em>

<em>=15a⁴ - 9a³  + 12a² + 25a³ - 15a² + 20a - 10a² + 6a - 8</em>

<em>= 15a⁴ </em><u><em>- 9a³ + 25a³</em></u><em>   +</em><u><em> 12a² - 15a² - 10a²</em></u><em>   +</em><u><em> 20a +6a </em></u><em>- 8</em>

<em>= 15a⁴ + 16a³  - 13a² +26a  - 8</em>

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3 years ago
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2x + 3y = 2<br> y = {x+3
FrozenT [24]

The solution of the system is (-2,2)

Step-by-step explanation:

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8 0
3 years ago
6. Find LCM (10,14,63).​
Katen [24]

Answer:

630 is the LCM

Step-by-step explanation:

You have to list all the multiples of each number till you find the lowest same value one which in this case it's 630.

Multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250, 260, 270, 280, 290, 300, 310, 320, 330, 340, 350, 360, 370, 380, 390, 400, 410, 420, 430, 440, 450, 460, 470, 480, 490, 500, 510, 520, 530, 540, 550, 560, 570, 580, 590, 600, 610, 620,<em> 630</em>, 640, 650

Multiples of 14:

14, 28, 42, 56, 70, 84, 98, 112, 126, 140, 154, 168, 182, 196, 210, 224, 238, 252, 266, 280, 294, 308, 322, 336, 350, 364, 378, 392, 406, 420, 434, 448, 462, 476, 490, 504, 518, 532, 546, 560, 574, 588, 602, 616, <em>630</em>, 644, 658

Multiples of 63:

63, 126, 189, 252, 315, 378, 441, 504, 567, <em>630</em>, 693, 756

3 0
3 years ago
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