Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
9514 1404 393
Answer:
140, 35, 260/35, 7.43, 8
Step-by-step explanation:
The last section is just a summary of the preceding sections, a short description of the problem and how you worked it.
She sells the jackets for 140% of $25, or $35. 260/35 = 7.43 She can only sell a whole number of jackets, so she needs to sell 8.
Answer:
x ≥ - 8
Step-by-step explanation:
Given
≥ - 4
Multiply both sides by 2 to eliminate the fraction
x ≥ - 8
Answer:
I think this is the answer
Step-by-step explanation:
angle 3
angle 4
angle 2 is 49
angle 1
Answer:
One adult ticket is $4 and one child ticket is $7
Step-by-step explanation:
Make a system of equations
2x + 10y = 78
8x + 5y = 67
Solve by elimination, multiply the 2nd equation by -2
2x +10y = 78
-16x -10y = -134
Add the equations
-14x = -56
x = 4
The price of one adult ticket is $4
Plug 4 in as x to find y
2(4) + 10y = 78
8 + 10y = 78
10y = 70
y = 7
The price of one child ticket is $7
