Answer:
<h2>
The right option is twelve-fifths</h2>
Step-by-step explanation:
Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.
Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;
Tan (A) = opp/adj
Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;
tan(A) = BC/AC
tan(A) = 24/10
tan(A) = 12/5
The right option is therefore twelve-fifths
I got 6x+3
The three equations are:
(2x-6) + (3x+1) + (x+8) =perimeter
2x+3x+x/1x=6x
-6+1+8= 3
Answer: 6
SOLUTION
∵segment
is tangent to the circle at point C.
∴∠MCA=∠MCB=90°
Suppose 
From the Pythagorean theorem
MA²=9²+
²
MB²=4²+²
∴MA²+MB²=AB²
i.e. 
We conclude that 
