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Explanation:</h2><h2>
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In this problem, we know that Harry saved $100 each week for 8 weeks. In other words, he saved a total amount of money:
We know that he earned $48 on his savings of $800, so for every $100 the interest (I) he earns is:
So, in conclusion Harry did earn $6 in interest for every $100
The test statistic <span>is
a value used in making a decision about the null hypothesis and is
found by converting the sample statistic to a score with the assumption
that the null hypothesis is true.
</span>
Let <em>q</em> be the number of quarts of pure antifreeze that needs to be added to get the desired solution.
8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.
The new solution would have a total volume of 8 + <em>q</em> quarts, and it would contain a total amount of 3.2 + <em>q</em> quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means
(3.2 + <em>q</em>) / (8 + <em>q</em>) = 0.60
Solve for <em>q</em> :
3.2 + <em>q</em> = 0.60 (8 + <em>q</em>)
3.2 + <em>q</em> = 4.8 + 0.6<em>q</em>
0.4<em>q</em> = 1.6
<em>q</em> = 4
Step-by-step explanation:
the area of a triangle is
baseline × height / 2
we have here 2 triangles : the larger, outer shaded one, and the smaller, inner white one.
to get the area of the shaded part, we need to calculate the area of the large triangle and subtract the area of the smaller triangle.
large area :
12 × 15 / 2 = 6 × 15 = 90 ft²
small area :
8 × 10 / 2 = 4 × 10 = 40 ft²
the shaded area is
90 - 40 = 50 ft²
For part A: two transformations will be used. First we will translate ABCD down 3 units: or the notation version for all (x,y) → (x, y - 3) so our new coordinates of ABCD will be:
A(-4,1)
B(-2,-1)
C(-2,-4)
D(-4,-2)
The second transformation will be to reflect across the 'y' axis. Or, the specific notation would be: for all (x,y) → (-x, y) New coordinates for A'B'C'D'
A'(4,1)
B'(2,-1)
C'(2,-4)
D'(4,-2)
Part B: The two figures are congruent.. We can see this a couple of different ways.
- first after performing the two transformations above, you will see that the original figure perfectly fits on top of the image.. exactly the same shape and size.
- alternatively, you can see that the original and image are both parallelograms with the same dimensions.
