Whats the vertex for y=2x^2 -4x-2

How much of a spice that is 3% salt should be added to 175 ounces of a spice that is 6% salt in order to make a spice that is 5%

Nonamiya [84]

Answer:

Let y represents the ounces of first spice.

From the given statements, we draw a table as shown below:

ounces of spice Percentage ounces of salt

First spice y 3% 0.03x

Second spice 175 6% 175(0.06)

Final mixture y + 175 5% (x+15)(0.05)

Now, to solve for y

we have;

Final spice = First spice + second spice

$0.03y + 175(0.06) = (y+175)(0.05)$

$0.03y+ 10.5= 0.05y+ 8.75$

Subtract 10.5 on both sides we have;

$0.03y+ 10.5 -10.5= 0.05y+ 8.75 -10.5$

Simplify:

$0.03y = 0.05y -1.75$

Subtract 0.05y on both sides

$0.03y -0.05y= 0.05y -1.75-0.05y$

Simplify:

$-0.02y = -1.75$

Divide both sides by -0.02, we get;

$y = \frac{-1.75}{-0.02} = 87.5$

Therefore, 87.5 ounces of spices that is 3% salt should be added to 175 ounces of a spice that is 6% salt in order to make a spice that is 5% salt

5 0

3 years ago

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I need help with this Math

Marianna [84]

Answer:

it would be 126.25 bro i got you.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Create an inequality, 5 less than a number is less than -2

____ [38]

Answer:

x - 5 < -2

Answer is there

5 0

3 years ago

Graph the following sequence of transformations for

Sedbober [7]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind.

$\bf f(x)=\sqrt[3]{x}\qquad \boxed{-f(x+2)+4}\implies f(x)=\stackrel{A}{-1}\sqrt[3]{\stackrel{B}{1}x\stackrel{C}{+2}}\stackrel{D}{+4}\qquad 
\\\\\\
f(x)=-\sqrt[3]{x+2}+4$

A = -1, reflected over the x-axis

B = 1, C = 2, horizontal shift of C/B or 2, to the left.

D = 4, shifted upwards by 4 units.

check the picture below.

7 0

3 years ago

A study of the annual population of gray squirrels in a Texas state park shows the population, S(t), can be represented by the f

Anastasy [175]

The growth rate of the given function is A) 1

Step-by-step explanation:

Step 1; To calculate the rate we need to see the difference between values at different periods of time. We need to calculate the population at different times.

For t = 1 years, S(t) = 273(1.073)t = 273 × 1.073 × 1 = 292.929,

For t = 2 years, S(t) = 273(1.073)t = 273 × 1.073 × 2 = 585.858,

For t = 2 years, S(t) = 273(1.073)t = 273 × 1.073 × 1 = 878.787.

Step 2; To calculate the growth rate, we divide the difference in the values of the present year and the past year by the value in the past year.

Growth rate between t = 1 and t = 2, Growth rate = S(t=2) - S(t=1) / S(t=1)

= 585.858 - 292.929 / 292.929 = 1.

Growth rate between t = 2 and t = 3, Growth rate = S(t=3) - S(t=2) / S(t=2)

= 878.787 - 585.858 / 585.858 = 1.

So the growth rate is A) 1.

4 0

4 years ago