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3 years ago

7

Which relation is a function?

1 answer:

ivolga24 [154]3 years ago

3 0

Answer:

the last one

Step-by-step explanation:

when looking for the function we have to know that none of the x values can repeat

in the first one the x value -5 repeats twice so that cannot be the answer

in the second one the x value 2 repeats twice so that cant be the answer

in the third one the x value -7 repeats twice so that also cannot be the answer

in the last one each x value has a different y value or every input has a different output therefore this one is the right answer

hope this helps :D

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Someone show equation form

Oliga [24]

Answer/Step-by-step explanation:

$\begin{gathered}\boxed{\begin{array}{c|c}\boxed{\bf Form} &\boxed{\bf Equation} \\ \sf Slope\: intercept\:form &\sf y=mx+b \\ \sf Intercept\:form &\sf \dfrac{x}{a}+\dfrac{y}{b}=1\\ \sf Normal\:form &\sf xcos\omega+ysin\omega=p \\ \sf Two\: point\:form &\sf y-y_1=\left(\dfrac{y_2-y_1}{x_2-x_1}\right)(x-x_1)\\ \sf Point\:slope\:form &\sf y-y_1=m(x-x_1) \\ \sf Standard\:form &\sf Ax+By+C=0 \end{array}}\end{gathered}$

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3 0

2 years ago

HELP!!!!!!!!!!!!!!!!!!

padilas [110]

First, factor each expression by finding two terms whose product is equal to the c term and sum is equal to the b term.

x^2-x+6 --> (x-3)(x+2)

x^2-4 --> (x+2) (x-2)

Next, cancel the terms that are equal on the top and bottom.

You are left with the answer of: $\frac{x-3}{x-2}$

Hope this helps!!

8 0

3 years ago

Mimi started a pattern whit 5 and used the rule add 10

guajiro [1.7K]

Answer:

This seems like an incomplete question...

Step-by-step explanation:

The pattern would go 5...15...25...35...45...55... and so on.

Hope this is the answer you were looking for!! :)

3 0

3 years ago

Subtract. (5x2−3x−2)−(−2x2−x+10) Express the answer in standard form. Enter your answer in the box.

Nimfa-mama [501]

Answer:

$7x^{2}-2x-12=0$

Step-by-step explanation:

we know that

The standard form of the quadratic equation is equal to $ax^{2} +bx+c=0$

we have

$(5x^{2}-3x-2)-(-2x^{2}-x+10)$

eliminate the parenthesis

$5x^{2}-3x-2+2x^{2}+x-10$

group terms that contain the same variable

$(5x^{2}+2x^{2})+(-3x+x)+(-2-10)$

combine like terms

$7x^{2}-2x-12=0$

5 0

4 years ago

Read 2 more answers

When you divide 4 by 7 quotient is a

suter [353]

The quotient would be about 0.571 (rounded)

3 0

4 years ago

Read 2 more answers