Sub 2 for x in j(x) and evalueate
then sub that result for x in h(x)
j(2)=-2(2)
j(2)=-4
now sub-4 for x in h(x)
h(-4)=5(-4)-3
h(-4)=-20-3
h(-4)=-23
answer is -23
Area of square = 4 square inches
Area of circle = PI * radius ^2
Area of circle = 3.14 * 1^2
Area of circle = 3.14 square inches
Area inside the square and outside the circle =
4 -3.14 = .86 square inches.
answer is .9 square inches
Answer: (0, 2)
3x = y - 2
6x = 4 - 2y
3x = y - 2
- y - y
-y + 3x = - 2
- 3x - 3x
-y = - 3x - 2
/-1 /-1
y = 3x + 2
6x = 4 - 2y
+ 2y + 2y
2y + 6x = 4
- 6x - 6x
2y = - 6x + 4
/2 /2
y = -3x + 2
y = 3x + 2
y = -3x + 2
3x + 2 = -3x + 2
- 2 - 2
3x = -3x
/3 /3
x = 0
y = 3x + 2
y = 3(0) + 2
y = 2
(x, y) --> (0, 2)
Therefore, the two equations intersect at (0, 2)
Hope this helps!
Greetings!
This can be solved by creating a simple equation.

Solve for x.

Find the LCM.


Add
-5/12 to both sides.

Simplify.

Find the LCM.


He kept 7/12 of the raisins for himself.
Hope this helps.
-Benjamin