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lara [203]
3 years ago
13

A rectangular computer monitor is measured by the length and width of its display resolution. Three different monitors are descr

ibed below. Monitor A has a display resolution of 640 pixels by 480 pixels. Monitor B has a display resolution of 800 pixels by 600 pixels. Monitor C has a display resolution of 1,280 pixels by 800 pixels. Which of the monitors are similar, based on their display resolution
Mathematics
1 answer:
Anna [14]3 years ago
3 0

Answer: Monitors A and B

Step-by-step explanation:

The similar monitors based on display resolution are those with similar ratios.

Take the ratios to their simplest forms to see which are similar.

Monitor A

= 640 : 480

= 16 : 12

= 4 : 3

Monitor B

= 800 : 600

= 8 : 6

= 4 : 3

Monitor C

= 1,280 : 800

= 32 : 20

= 8 : 5

<em>Monitors A and B are similar as they have the same display ratio. </em>

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The marginal profit at a production/sales level of 6000 pounds of popcorn is –2.40
ivolga24 [154]

Answer:

Booger are nasty!! dont eat them

Step-by-step explanation:

3 0
3 years ago
X/2 + 4/5 = 1/2 solve for x​
Flura [38]

Answer:

<h3>              x = -3/5</h3>

Step-by-step explanation:

x/2 + 4/5 = 1/2

        ×2       ×2

  x + 8/5  = 1

    -8/5        -8/5

           x = 5/5 - 8/5

           x = -3/5      

3 0
4 years ago
What is the period and midline?
OverLord2011 [107]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;&#10;\end{array}\qquad

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\&#10;&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;\bullet \textit{function period}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}&#10;

so if you notice yours \bf \begin{array}{llll}&#10;3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\&#10;&\ \uparrow&\uparrow \\&#10;&B&D &#10;\end{array}

now.. normally the function \bf 3.2cos&\left( \frac{5}{3}\theta \right)
 has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline  up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is 2\pi
so, the new period will be \bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0
3 years ago
R/10+4=5 answer plzz
Maksim231197 [3]

Answer:

r = 10

Step-by-step explanation:

Solve for  r  by simplifying both sides of the equation, then isolating the variable.

7 0
4 years ago
What are the next two numbers in the pattern 2,7,22,67,
Gennadij [26K]

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67-22=45

First, we add 20+30 to 67 to find our next number.

67+50=117

Then we add 20+50 to 117 to find the next number.

117+70=187

So the next 2 numbers in the sequence is 117 and 187.

hope it helps!

4 0
3 years ago
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