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valentinak56 [21]

3 years ago

14

Boreal forests are characterized by _______ trees. A. Creosote b. Eucalyptus c. Coniferous d. Deciduous Please select the best a

nswer from the choices provided A B C

2 answers:

cluponka [151]3 years ago

5 0

Answer: C is correct.

Aleonysh [2.5K]3 years ago

3 0

Answer:

c

Explanation:

coniferous trees, Tianga also called Boreal forest biome (major life zone).

hope it's perfect.

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Convert 1176 mmHg to kPa

OLEGan [10]

Answer:

156.8kPa

Explanation:

The problem here is to convert mmHg to kPa;

We have been given:

1176mmHg and the problem is to convert to kPa;

1000Pa = 1kPa

1 mmHg = 133.322Pa

1176mmHg will give 1176 x 133.322 = 156787.1Pa

To kPa;

156.8kPa

8 0

3 years ago

The constant volume heat capacity of a gas can be measured by observing the decrease in temperature when it expands adiabaticall

miv72 [106K]

Answer:

The value is $C_p = 42. 8 J/K\cdot mol$

Explanation:

From the question we are told that

$\gamma = \frac{C_p }{C_v}$

The initial volume of the fluorocarbon gas is $V_1 = V$

The final volume of the fluorocarbon gas is $V_2 = 2V$

The initial temperature of the fluorocarbon gas is $T_1 = 298.15 K$

The final temperature of the fluorocarbon gas is $T_2 = 248.44 K$

The initial pressure is $P_1 = 202.94\ kPa$

The final pressure is $P_2 = 81.840\ kPa$

Generally the equation for adiabatically reversible expansion is mathematically represented as

$T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }$

Here R is the ideal gas constant with the value

$R = 8.314\ J/K \cdot mol$

So

$248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }$

=> $C_v = 31.54 J/K\cdot mol$

Generally adiabatic reversible expansion can also be mathematically expressed as

$P_2 V_2^{\gamma} = P_1 V_1^{\gamma}$

=> $[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}$

=> $2^{\gamma} = 2.56$

=> $\gamma = 1.356$

So

$\gamma = \frac{C_p}{C_v} \equiv 1.356 = \frac{C_p}{31.54}$

=> $C_p = 42. 8 J/K\cdot mol$

3 0

3 years ago

A 2.8-kg pile of aluminum (rho = 2.70 g/cm3) cans is melted, then cooled into a solid cube. What is the volume of the cube?

k0ka [10]

Answer:

Explanation:

mass of aluminum 2.8 kg = 2.8 x 1000 = 2800 g

ρ = density of aluminum given = 2.7 g / cm³

density = mass / volume

volume = mass / density

= 2800 / 2.7

= 1037 cm³

So volume of cube required = 1037 cm³.

8 0

3 years ago

3. The chemical formula of a compound does NOT indicate _____.

mamaluj [8]

Answer:

Im pretty sure its 2 How elements are joined in the compound

Explanation:

6 0

4 years ago

Read 2 more answers

Calculate the number of pounds of CO2 released into the atmosphere when a 22.0 gallon tank of gasoline is burned in an automobil

IrinaK [193]

Answer:

391.28771 pounds of carbon-dioxide released into the atmosphere.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasolin be M

$d=\frac{M}{V}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Assume that gasoline is primarily octane (given)

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08 g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide released into the atmosphe

4 0

4 years ago