Moles of ammonia
- Given mass/Molar mass
- 230/17
- 13.5mol
1mol requires 5.66KJ energy
13.5mol requires
Initial pressure of the gas = 65.3 kPa
Initial volume of the gas = 654 cm³
Initial temperature of the gas = 6⁰C = 273 + 6 = 279 K
Final pressure of the gas = 108.7 kPa
Final temperature of the gas = 4⁰C = 273 + 4 = 277 K
Using the combined gas law for ideal gases:
P₁V₁/T₁ = P₂V₂/T₂
where P₁, V₁ and T₁ are the pressure, volume and temperature for the initial state and P₂, V₂ and T₂ are the pressure, volume and temperature for the final state.
Plugging the given data into the combined gas law we have,
(65.3 kPa x 654 cm³) / (279 K) = (108.7 kPa x V₂)/(277 K)
V₂ = (65.3 kPa x 654 cm³ x 277 K) / (279 K x 108.7 kPa)
V₂ = 390.1 cm³
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Explanation:
Answer:
he composition of matter is invisible particles called atoms.
Explanation:
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Answer:
The physical property is density
