3 years ago

Question 5 of 5

Chemistry

2 answers:

rjkz [21]3 years ago

8 0

Probably Fresh vegetables, it can rot out, that’d be my guess, it’s not canned

amid [387]3 years ago

6 0

Answer:

probably fresh vegetables

Explanation:

cause it consumes off the ground

You might be interested in

A scientific theory is

vlada-n [284]

The answer is A. an explanation

7 0

3 years ago

One way to limit iron corrosion is to coat the iron with a metal that:

Lorico [155]

<span>1.)One way to limit iron corrosion is to coat the iron with a metal that:
A.)will never undergo corrosion

</span>

3 0

3 years ago

Read 2 more answers

A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h

frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

$Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]$

Where;

$\frac{f_2}{f_1}$ is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

$Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1} = 10^{0.7289}\\\\\frac{f_2}{f_1} = 5.356$