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alisha [4.7K]
2 years ago
6

Question 5 of 5

Chemistry
2 answers:
rjkz [21]2 years ago
8 0
Probably Fresh vegetables, it can rot out, that’d be my guess, it’s not canned
amid [387]2 years ago
6 0

Answer:

probably fresh vegetables

Explanation:

cause it consumes off the ground

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Based on your energy level calculations, predict the photon energies that would be emitted by transitions between the hydrogen e
mote1985 [20]

Answer:

The formula defining the photon energies that would be emitted by transitions between the hydrogen energy levels are given by the equation:

ΔE = -13.6Z²[1/n₁² - 1/n₂²]eV, where  (1 eV = 1.602×10-19 Joules) and n₁ = initial energy level  and n₂ = final energy level.

Z = Atomic number of the atom

8 0
3 years ago
Which of the following is an example of organic matter salt water or air​
bonufazy [111]

Answer:

I believe it is air.

Explanation:

7 0
2 years ago
What is the bronsred base of NO2- +H2O HNO2 +OH-
kramer
Bronsted lowry bases

NO2- amd OH-
4 0
3 years ago
Dan got into his car in the middle of summer. When he sat on the hot black leather seats, he burned his legs. His sister said th
LekaFEV [45]

The correct answer is D) Dan's sister was correct because Dan's legs touched the car seats. That is an indicator of heat transfer by conduction.

Conduction only happens when a heated object touches a non-heated (or not as heated) object. Radiation did cause the car to become hot, but conduction caused Dan to get burned.

Hope this helps!! :D

3 0
3 years ago
Read 2 more answers
When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6
Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

Explanation:

Wavelength of the photon emitted = \lambda =646.3 nm =646.3\times 10^{-9} m

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

E=\frac{hc}{\lambda }

h = Planck's constant = 6.626\tiomes 10^{-34} Js

c = Speed of the light = 3\times 10^8 m/s

E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}

E=3.07\times 10^{-19} J

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

3 0
3 years ago
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