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tamaranim1 [39]
3 years ago
10

Van der Waals forces hold molecules together by: A. moving electrons from one molecule to another. B. attracting a lone pair of

electrons to the positive charge of a hydrogen. C. inducing temporary dipoles that attract each other. D. sharing electrons between atoms.
Chemistry
1 answer:
Rasek [7]3 years ago
6 0

The forces that are existing between molecules are known as intermolecular forces. These forces which are weaker than ionic and covalent bonds are classified into three types'

--> dipole-dipole attraction

--> VAN DER WAALS FORCES and

--> hydrogen bonding.

Van Der Waals forces was postulated by a Dutch physicist known as Van Der Waals. He postulated the existence of weak, short-range forces of attraction, which are independent of normal bonding forces, between non-polar molecules. He came to this conclusion after studying the behaviour of real gases at low temperatures and high pressures that:

--> electrons in a non-polar molecule such as hydrogen are close to one nucleus as to the other, although momentary concentration at one end of the molecule may occur,

--> this momentary concentration of electron cloud on one side create a temporary dipole in the hydrogen molecule, that is, one side of the molecule acquires a partial negative charge while the other side acquires a partial positive charge of equal magnitude,

--> the temporary dipole induces a similar dipole in an adjacent molecule,

--> this results in a temporary dipole-induced dipole attraction between the positive and negative ends of the adjacent molecules.

This is how weak Van Der Waals forces are set up. Therefore, option C is CORRECT which states that VAN DER WAALS forces hold molecules together by inducing temporary dipoles that attract each other.

Learn more about Van Der Waals forces here:

brainly.com/question/11457190

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Consider the following reaction: 2{\rm{ N}}_2 {\rm{O(}}g)\; \rightarrow \;2{\rm{ N}}_2 (g)\; + \;{\rm{O}}_2 (g)
fredd [130]

Answer:

a. 5.9 × 10⁻³ M/s

b. 0.012 M/s

Explanation:

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2 N₂O(g) → 2 N₂(g) + O₂(g)

a.

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We can find the average rate of the reaction over this time interval using the following expression.

r = Δn(O₂) / V × t

r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s

r = 5.9 × 10⁻³ M/s

b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:

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4 0
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Consider the structures of vinegar and triglyceride and draw in any bond dipoles that exist in the molecules above using a dipol
bagirrra123 [75]

Answer:

Given molecules are vinegar and triglycerides.

Explanation:

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The structures and the bond dipoles in the given molecules are shown below:

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