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3 years ago

(-3)*(2a+b)-4(b-a) I WILL AWORD BRILLEEST

Mathematics

1 answer:

Fynjy0 [20]3 years ago

4 0

Answer:

-3(2a+b)4+a/(2a+b)4

Step-by-step explanation:

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grin007 [14]

Answer:

because all triangle's interior angles add up to 180 degrees so and angles 8 and 9 are supplementary. Angle 9 is 77 degrees.

Step-by-step explanation:

because all triangle's interior angles add up to 180 degrees so and angles 8 and 9 are supplementary. Angle 9 is 77 degrees.

6 0

3 years ago

How do i solve n squared - 62

snow_lady [41]

The rule for this one is called the difference of squares
A^2 - b ^2 = (a+b)(a-b)

Using this rule
N^2 - 62 = (n+ sqrt(62)) (n - sqrt(62))

The solution for this one is to make the statement = 0
0 = (n+ sqrt(62)) (n - sqrt(62))

N can either be +- sqrt(62)

5 0

3 years ago

What is the area of the top of the can if the radius is 8 cm?

just olya [345]

Answer:

64π

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

5 0

3 years ago

What value of x makes this equation true? 4r - 10 = 18

Bond [772]

X= 7
This is because of you plug in 7 for x into the equation it will give you 28-10 which is 18.

6 0

3 years ago

V2=u2+2as v 2 = u 2 + 2 a s Where v v is the final velocity (in m/s), u u is the initial velocity (in m/s), a a is the accelerat

allsm [11]

Answer:

Final velocity, v = 21.75 m/s

Step-by-step explanation:

Given that the relation between final velocity, initial velocity, acceleration and distance traveled is expressed as:

$v^2=u^2+2as$

Also, given that:

Initial velocity, u = 9 m/s

Acceleration, a = 7 m/ $s^2$

Distance, s = 28 m

To find:

Final velocity, v = ?

Solution:

The given relation between v, u, a and s is:

$v^2=u^2+2as$

We have the values of initial velocity, acceleration and distance traveled in the question statement. We just need to put all these values to find the value of final velocity.

Let us put all the values in the given equation and try to find final velocity, v:

$v^2=9^2+2\times 7 \times 28\\\Rightarrow v^2=81+14 \times 28\\\Rightarrow v^2=81+392\\\Rightarrow v^2=473\\\Rightarrow v=\sqrt{473}\\\Rightarrow v=21.75\ m/s$

So, the answer is:

final velocity, v = 21.75 m/s

5 0

3 years ago