Question

2. The Population of Brownsville is 20,000 in year 2010. Using the function P(t)= (20,000) (1.15)

Answer 1

Given:

The Population of Brownsville is 20,000 in year 2010.

Consider the population function

$P(t)=20000(1.15)^t$

To find:

The population in 2012.

Solution:

The population function of Brownsville is

$P(t)=20000(1.15)^t$

The Population of Brownsville is 20,000 in year 2010.

So, the given function P(t) represents the population of Brownsville after t years of 2010.

2012 is 2 years after 2010.

Putting t=2 in P(t), we get

$P(2)=20000(1.15)^2$

$P(2)=20000(1.3225)$

$P(2)=26450$

Therefore, the Population of Brownsville is 26,450 in year 2012.