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zysi [14]
3 years ago
11

6 times the sum of yand 11

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0

6*11*11*11*11*11*11=10629366

larisa86 [58]3 years ago
7 0

Answer:

6(y+11)

Step-by-step explanation:

hope this helps

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A number less than 15
artcher [175]

Answer:

14,13,12,11,10,9,8,7,6,5,4,3,2,1

Step-by-step explanation:

hope this helps

6 0
3 years ago
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Help me please number 7 (please show work)
astra-53 [7]

Answer:

m<H=30 degrees by the Triangle Sum Theorem, so <H=<V. <G=<U, they are right angles. If GH=UV, triangle FGH=triangle TUV by the ASA.

x=3  and y=8

Step-by-step explanation:

H equals 30 by 180-150=30 (getting 150 by adding 60 and 90)

I know this is not much of a answer, but I hope it helps a little.

http://www.somersetkey.com/ourpages/auto/2017/12/13/63309824/geo%20ch%205%20sec%204%20teach.pdf

8 0
3 years ago
You are testing a claim and incorrectly use the normal sampling distribution instead of the​ t-sampling distribution. Does this
Keith_Richards [23]

Answer:

From the given data, the typical appropriation is utilized rather than t distribution for testing. The thicknesses of the curve similarly influence both normal distribution and territory of t distribution. The normal distribution test and t test give a similar dismissal for the invalid theory for any tail of the test. Besides, the tests normal sampling distribution and t sampling distribution give a similar dismissal to null hypothesis.  

Along these lines, the outcomes got by utilizing normal distribution and t distribution are distinguished as same and for each situation, the tail thickness doesn't influence the event of the basic qualities.

8 0
3 years ago
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A circle with area 9 pie has a sector with a central angle of 17/9 pie radians .
zmey [24]

Answer:  8.5π

<u>Step-by-step explanation:</u>

If I understand the question correctly, the entire circle has an Area of 9π and you are looking for the Area of the shaded region which has a central angle of \dfrac{17}{9}\pi

the section of the circle that is shaded is \dfrac{\dfrac{17}{9}\pi}{2\pi}=\dfrac{17\pi}{18\pi}=\dfrac{17}{18}

Area of the shaded region is: 9\pi \cdot \dfrac{17}{18}=\dfrac{17}{2}\pi=8.5\pi

5 0
4 years ago
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A study was conducted to see if students from public high schools were more likely to attend public colleges compared to student
bogdanovich [222]

Answer:

B

Step-by-step explanation:

We are 90% confident the proportion of students planning to attend public colleges who attended public high schools is between 0.0152 lower than to 0.2152 higher than the proportion of students planning to attend public colleges who attended private high schools.

4 0
3 years ago
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