Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.
Step-by-step explanation:
all I see is a piece of paper
4- 7x = 23- 5
4 - 7x = 18
-4 = -4
-7x = 14
/-7 = /-7
X = -2
3x = -6
First we have the following equation:
a - b = 0
We clear one of the variables depending on the other:
a = b
Therefore we have to for the following expression:
a + b
We can substitute one of the variables, obtaining:
a + a = 2a
Equivalently:
b + b = 2b
Answer:
a + b = 2a
or
a + b = 2b
