Answer:
The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.
Step-by-step explanation:
Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

In the first year the value of the printer is:

On the second year the value of the printer is:

On the third year the value of the printer is:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.
X= 2.737 - look on the website "Tiger algebra for the answer by typing in the question
LCM OF 24, 34, 30, 36:
What is something we can multiply by that will give us all the answers? The # would be 2.
The easiest thing to do to solve all of these is to use the quadratic equation.

The first number (the one attached to x^2) is equal to a. The second number (the one attached to x) is b. The final number (the one with nothing attached) is c.