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serious [3.7K]
3 years ago
6

Please help me with the question ​

Mathematics
1 answer:
Damm [24]3 years ago
7 0

Answer:

The right answer is Option 2:

y+6 = -\frac{3}{4}(x-2)

Step-by-step explanation:

Point-slope form of equation of a line is given by:

y-y_1 = m(x-x_1)

Here m is slope of the line and (x1,y1) is the point from which the line passes.

Given

Slope = m = -3/4

Point = (x1,y1) = (2,-6)

We simply have to put these value into the general form of equation of line in point-slope form

y-(-6) = -\frac{3}{4}(x-2)\\y+6 = -\frac{3}{4}(x-2)

Hence,

The right answer is Option 2:

y+6 = -\frac{3}{4}(x-2)

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Lee Company has a current ratio of 2.65. The acid test ratio is 2.01. The current liabilities of Lee are $45,000. Assuming there
Salsk061 [2.6K]
The dollar amount of merchandise inventory is A. $28,800
Let N = be the missing number
1.) 
N/$45,000 = 2.65/1 (cross multiply to get the current assets)
                   N = $119,250
2.) N/$45,000 = 2.01 (cross multiply to get current the quick assets)
                   N = $90,450
3.) Since there are no prepaid expenses, subtract current quick assets from the current assets to get the merchandise inventory
$119,250 - $90,450 = $28,800
8 0
3 years ago
In an election, the population consists of the people who voted. Although there is overall data on how the population voted, the
andrew-mc [135]

Answer:

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

Step-by-step explanation:

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4 0
3 years ago
Whats the answer? Please respond ASAP!
Artemon [7]

Answer:

C.

Step-by-step explanation:

4 0
3 years ago
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Full-time ph.d. students receive an average of $12,837 per year with a standard deviation of $3000. find the probability that th
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It is about 41.4% according to my TI-83/84 calculator.

7 0
3 years ago
......................​
ExtremeBDS [4]

Answer:

the question is about the table you have to make a table it is very easy

6 0
3 years ago
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