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Readme [11.4K]
3 years ago
12

What are the coordinates of the image of the point (1-, 2) under a dilation of 3 with the origin

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

Answer:

The image of the point (1, -2) under a dilation of 3 is (3, -6).

Step-by-step explanation:

Correct statement is:

<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>

From Linear Algebra we get that dilation of a point with respect to another point is represented by:

\vec P' = \vec R + r\cdot (\vec P-\vec R) (Eq. 1)

Where:

\vec R - Reference point with respect to origin, dimensionless.

\vec P - Original point with respect to origin, dimensionless.

r - Dilation factor, dimensionless.

If we know that \vec R = (0,0), \vec P = (1, -2) and r = 3, then the coordinates of the image of the original point is:

\vec P' = (0,0) +3\cdot [(1,-2)-(0,0)]

\vec P' = (0,0) + 3\cdot (1,-2)

\vec P' = (3,-6)

The image of the point (1, -2) under a dilation of 3 is (3, -6).

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Answer:

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Now

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3 0
3 years ago
Nine times a number decreased by 16
Setler79 [48]

Answer:

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Explanation:

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Help ASAP!!! Savings Account.Christine Chu borrowed $4500 from a bank at a simple interest rate of 2.5% for one year.
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Answer: $112.50 ; $4612.5

Step-by-step explanation:

a) Determine how much interest Christine paid at the end of 1 year.

This will be:

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where

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R = rate = 2.5%

T = time = 1 year

Interest = (4500 × 2.5 × 1)/100

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b) Determine the total amount Christine will repay the bank at the end of 1 year.

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= $4612.5

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Fudgin [204]
The third one
5/6 is the answer
7 0
3 years ago
Read 2 more answers
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