Parallel means it has the same slope.

Slope in thisproblem is -5/4.

This means the slope of the parallel line is also -5/4.

Perpendicular is the reciprical of the slope.

Flip the slope and make it +/-.

The slope would be 4/5.

5 0

4 years ago

In a random sample of 192 college students, 129 had part-time jobs. find the margin of error for the 95% confidence interval use

Setler [38]

<span>Given data show that 129 college students out of 192 have part time jobs. proportion p = 129/192 = 0.672 The estimated population proportion is p* = 0.672 Standard error = squareroot of [p*(1 - p*)/n] = 0.034 Value for 95% confidence interval = 1.96 margin of error = 1.96 x 0.034 = 0.067</span>

5 0

4 years ago

Plss hellppp. Worth 10 points<3

Alex Ar [27]

Answer:

writing a poem about someone who has died

Step-by-step explanation:

lyric poems are deep, emotional, and powerful, thus the selected option should be best for that

5 0

2 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

3 years ago