Letter C
The - 3 at the end of the function means the function is shifted down 3 units. This also shifts the asymptote down 3 units.
Slope intercept form is y=mx+b because m=slope and b=y-intercept hence "slope intercept form"...
m=deltay/deltax=(0-5)/(-9--6)=-5/-3=5/3 so far we have now:
y=5x/3 +b, using any point, I'll use (-9,0) we can now solve for b or the y-intercept...
0=-9(5)/3 +b
0=-15+b, so b=15 and our line is:
y=5x/3 + 15 or more neatly
y=(5x+45)/3
(gof)(0) cannot be evaluated
<em><u>Solution:</u></em>
Given that,
A composite function is denoted by (g o f) (x) = g (f(x)).
The notation g o f is read as “g of f”
Therefore, let us find whether (gof)(0) can be evaluated or not
To find (gof)(0):
(g o f) (x) = g (f(x))
Now substitute the given value of f(x)
Now to find (gof)(0), substitute x = 0
Since 1 divided by 0 is undefined, because any number divided by 0 is undefined
(gof)(0) cannot be evaluated
The correct question is
<span>What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3
</span>
we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0
the answer is
<span>x - 3y - 7 = 0</span>
The function shown is f(x)= -1/2 cos(x).
sin(x) makes the line way more “curverier” So both sin(x) functions are out. It is NOT 1/2 cos(x) because it would make the y-intercept 0, not .5 In the picture it’s starting at .5 so it’s f(x)=-1/2 cos(x)
