Question

Given f(x)=x(x-3)+4 what is the derivative of f at a?

Answer 1

$f(x) = {x}^{2} - 3x + 4 \\ \frac{d}{dx} ( {x}^{2} - 3x + 4) \\ g(x) = 2x - 3$

Let g(x) = f'(x)

Substitute a in x, therefore the answer is.

$g(a) = 2a - 3$

— Note that it'd be better to use f'(a) or y' instead. For this one, I let g(x) equal the derivative of f(x) —