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NikAS [45]
3 years ago
9

Classify the triangle by its sides the lengths of the sides are 6,8,and 8

Mathematics
2 answers:
Andreyy893 years ago
8 0

Answer:

The given sides belong to an isosceles triangle.

Step-by-step explanation:

There are three types of triangles that can be identified, based on their sides.

1. Equilateral triangle. This triangle has all the three sides equal in length.

2. Isosceles triangle. This triangle has 2 sides equal in length.

3. Scalene triangle. This triangle has no sides equal.

Here, we have been given, that a triangle has sides 6 units, 8 units and 8 units.

We can see that two sides have equal length. So this is an isosceles triangle.

Alina [70]3 years ago
3 0
Answer: isosceles triangle!
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Jackson used 8/9 of a case of soda to fill 1/3 of the soda machine. How many cases does it take to fill the soda machine?
lorasvet [3.4K]
Jackson used 8/9 of a case of soda to fill 1/3 of the soda machine.
how many cases does it take to fill the soda machine = ?
1/3 means three parts of the soda machine, it means if we fill with 8/9 of a case three times soda machine will be full so,
8/9 + 8/9 + 8/9 = 24/9 
it means it takes the case of soda between 2 and 3.
2.667 approx. cases of soda it take to fill the soda machine.
8 0
3 years ago
Can someone help me w this pls
RSB [31]

Answer:

a = 2b/c

Step-by-step explanation:

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2 years ago
The intersection of the two sides of an angle is called it’s?
Anna71 [15]

Answer:

Point

Step-by-step explanation:

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3 years ago
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mixas84 [53]

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2 years ago
find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:
lbvjy [14]

Answer:

a = 4

b = -2

Step-by-step explanation:

If the given function is continuous at x = 1

\lim_{x \to 1^{-}} f(x)=(x+1)

                     =2

\lim_{x \to 1^{+}} f(x)=ax+b

                     =a+b

\lim_{x \to 1} f(x)=ax+b

                   =a+b

And for the continuity of the function at x = 1,

\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

\lim_{x \to 2^{-}} f(x)=ax+b

                     =2a+b

\lim_{x \to 2^{+}} f(x)=3x

                     =6

\lim_{x \to 2} f(x)=3x

                   =6

Therefore, \lim_{x \to 2^{-}} f(x)=\lim_{x \to 2^{+}} f(x)=\lim_{x \to 2} f(x)

2a + b = 6 -----(2)

Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

3 0
3 years ago
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