Two consecutive integers have a sum of 55 find the integers

Mathematics

1 answer:

Stels [109]3 years ago

5 0

Answer:

27, 28

Step-by-step explanation:

I like to work problems like this by considering the average of the two integers. Here, it is 55/2 = 27.5. This is halfway between consecutive integers 27 and 28, which have a sum of 55.

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Six times a number x and was added to 90 and the result is -42. What is the number

ANTONII [103]

According to the question,

6x + 90 = -42

The value of x.

<h3>Solution:</h3>

6x = -42 + 90

or, x = 48/6

or, x = 8

<h2>Answer:</h2>

The value of x is 8.

6 0

3 years ago

Anyone who answers correctly is getting marked as Brainliest !!!!! PLEASE HELP

Nitella [24]

First, see how far she can go with 1 tank of gas:
160/5=32

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3 0

4 years ago

Select 3 expressions that have a sum or difference of 3 /4 .

cupoosta [38]

Answer:

The Three expressions that have a sum or difference of 3 /4 .

B . 11/12 − 1/6

C. 3/5 + 3/20

E . 2/3 + 1/12

Step-by-step explanation:

The Three expressions that have a sum or difference of 3 /4 .

are

B . 11/12 − 1/6

$\dfrac{11}{12}-\dfrac{1}{6}=\dfrac{11}{12}-\dfrac{1\times 2}{6\times 2}\\\\\dfrac{11}{12}-\dfrac{1}{6}=\dfrac{11}{12}-\dfrac{2}{12}=\dfrac{11-2}{12}=\dfrac{9}{12}=\dfrac{3}{4}$

Therefore,

$\dfrac{11}{12}-\dfrac{1}{6}=\dfrac{3}{4}$

C. 3/5 + 3/20

$\dfrac{3}{5}+\dfrac{3}{20}=\dfrac{3\times 4}{5\times 4}+\dfrac{3}{20}\\\\\dfrac{3}{5}+\dfrac{3}{20}=\dfrac{12}{20}+\dfrac{3}{20}=\dfrac{15}{20}=\dfrac{3}{4}$