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MissTica
3 years ago
11

Which graph below has an x intercerpt of four and a white intercerpt of negative two

Mathematics
1 answer:
sergiy2304 [10]3 years ago
7 0

Answer: you need to add a picture, otherwise we don’t know how to help you answer that questions

Step-by-step explanation:

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- 3 3/4 divided by 3
yarga [219]
This is the calculator I use to help solve problems I have in math, so it might be helpful, the answer would be -.75 as showed on the calculator/picture above.

6 0
3 years ago
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Prove that 3^17−3^15+3^13 is divisible by 73.<br><br> HELPPPPPP PLEASEEE
Fiesta28 [93]

Answer:

Well 3^17-3^15+3^13 equals 116,385,579

Now divide that by 73

So 116,385,579 ÷ 73

That equals 1,594,323

Hope this helps

4 0
3 years ago
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andrew and his father are scuba at -38 feet and tackle box canyon is -83 feet. write an inequality to compare the depths
KATRIN_1 [288]
-38 > -83

I have to use more charterers so I will explain it as well as I can. For example, If I am $38 in dept (-38) and you are $83 in dept (-83) who owes more money? Yes we both owe money but I owe LESS money.  
3 0
4 years ago
Enter the equation of the line in slope-intercept form. Slope is -6,and (4,3) is on the line. The equation of the line is
kakasveta [241]

Answer:

Step-by-step explanation:

y - 3 = -6(x - 4)

y - 3 = -6x + 24

y = -6x + 27

4 0
3 years ago
Minimum Average Cost
Dahasolnce [82]

Answer:

a)\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

b)\bar{C}(x)=5.81

Step-by-step explanation:

Given that

C = 100 + 25 x - 120 ln x   ,x ≥ 1.

The average cost function given as

\bar{C}(x)=\dfrac{C(x)}{x}

\bar{C}(x)=\dfrac{100 + 25 x - 120 \ln x}{x}

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx{x}

Therefore

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

To find average minimum cost

\bar{C}(x)=\dfrac{100}{x}+25-120\dfrac{lnx}{x}

\dfrac{d\bar{C}(x)}{dx} = -\dfrac{100}{x^2} +0-120\times \dfrac{1-lnx}{x^2}

0 = -\dfrac{100}{x^2} +0- 120\times \dfrac{1-lnx}{x^2}

100 + 120 (1-lnx) = 0

lnx=\dfrac{220}{120}

ln x =1.833

x=e^{1.833}

x=6.25

\bar{C}(x)=\dfrac{100}{6.25}+25-120\dfrac{ln6.25}{6.25}

\bar{C}(x)=5.81

6 0
4 years ago
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