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MariettaO [177]
2 years ago
13

Prove that 3^17−3^15+3^13 is divisible by 73. HELPPPPPP PLEASEEE

Mathematics
2 answers:
Fiesta28 [93]2 years ago
4 0

Answer:

Well 3^17-3^15+3^13 equals 116,385,579

Now divide that by 73

So 116,385,579 ÷ 73

That equals 1,594,323

Hope this helps

mylen [45]2 years ago
3 0

Answer: 3^13*73

Step-by-step explanation:

3^17-3^15+3^13 So you factor out 3^13

=3^13(3^4-3^2+1)

3^4-3^2+1=73

3^13*73

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Pllllllllllllllllllllleasee one guys i neeed ur help one
Svetllana [295]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

Calculate discriminant :

\qquad \sf  \dashrightarrow \: 3 {x}^{2}  + 6x - 1

  • a = 3
  • b = 6
  • c = 1

\qquad \sf  \dashrightarrow \: discriminant =  {b}^{2}  - 4ac

\qquad \sf  \dashrightarrow \: d = (6) {}^{2}  - (4 \times 3 \times 1)

\qquad \sf  \dashrightarrow \: d = 36 - 12

\qquad \sf  \dashrightarrow \: d = 24

\qquad \sf  \dashrightarrow \:  \sqrt {d} = 2 \sqrt{6}

Now, let's calculate it's roots ( x - intercepts )

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - b  \pm \sqrt{d} }{2a}

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6\pm 2 \sqrt{6}  }{2 \times 3}

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6\pm 2 \sqrt{6}  }{6}

So, the intercepts are :

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6 -  2 \sqrt{6}  }{6}

and

\qquad \sf  \dashrightarrow \: x =  \cfrac{ - 6  +  2 \sqrt{6}  }{6}

5 0
2 years ago
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PLEASE HELP 50 points
hoa [83]

Answer:

r > 7 (C)

Step-by-step explanation:

3r−7>14

Step 1: Add 7 to both sides.

3r−7+7>14+7

3r>21

Step 2: Divide both sides by 3.

3r

3

>

21

3

r>7

Hope this helps and makes sense!! Good luck and have a wonderful day! <33

Imagine this < as a alligater and itś eating the greater number!!

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