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3 years ago

The area of a rectangular field is 8811 m2. if the width of the field is 89m, what is the length?

1 answer:

4 0

Length = 99 because...
since you multiply to get the area, in order to find the missing term of an area (in this case its length), you do the opposite of what you started with...so if you multiplied to get the area, you need to divide to get the missing side...
so 8811 divided by 89 = 99
99 x 89 = 8811

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31.5*2.2 or 69.3 pounds.

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Mr. Hayden's Bible class collected $11

ki77a [65]

This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol

Answer:

Quarters: 18.909

Nickels: 49.818

Dimes: 37.818

Somewhere around those numbers.

Step-by-step explanation:

$11.00 total in coins

Nickel = $0.05

Dime = $0.10

Quarter = $0.25

(n*0.05) + (d*0.10) + (q*0.25)

Solve the equation for q.

$q=\frac{1}{2} d$

(n*0.05) + (d*0.10) +( $\frac{1}{2} d$ *0.25)

Simplify the expression.

9d + 2n = 440

d - n = -12

Multiply both sides of the equation by -9.

-9d + 9n = 108

9d + 2n = 440

Sum the equations vertically to eliminate at least one variable.

11n = 548

$n=\frac{548}{11}$

Substitute the given value of n into the equation d - n = -12

$d-\frac{548}{11} =-12$

$d=\frac{416}{11}$

Substitute the given value of n into the equation $q=\frac{1}{2} d$

$q=\frac{1}{2} *\frac{416}{11}$

$q=\frac{208}{11}$

Finally

$d=\frac{416}{11}$ d = 37.818

$n=\frac{548}{11}$ n = 49.818

$q=\frac{208}{11}$ q = 18.909

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2 years ago