Answer:
Tina is first
Tony is first
Theo is first
Step-by-step explanation:
Events with greater probability are more likely.
Let's put the probabilities in decimal form.
P(Tina is first) = 0.05
P(Theo is first) = %85 = 0.85
P(Tony is first) = 1/10 = 0.1
0.05 < 0.1 < 0.85
The events are listed below from least to most likely.
Tina is first, Tony is first, Theo is first
hope it helps
what do you have to do???
Hi!
I'm not sure how to slove this, but I do know how to solve it ;D
<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>
x + y = 3 * z
<h3>Now subtract x from both sides.</h3>
x - x + y = 3 * z - x
<u>y = 3 * z - x</u>
<h2>The answer is y = 3 * z - x</h2>
Hope this helps! :)
-Peredhel
Answer:
6,000:3
Step-by-step explanation:
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
