Quotient is the result of a division.
The quotient of 8 and a number is the division of 8 and a number.
8/z
Answer is C.
Exact Form:
t=1+√61/6,1−√61/6
t=1+61/6,1-61/6
Decimal Form:t=1.46837494…,−1.13504161
Answer:
345,512
Step-by-step explanation:
one liter is a thousand ml, so u just have to multiply
Here, you're mixing scores 85 and 90 with weights X and Y, respectively. You are asked for the ratio of X to Y.
There's a quick way to work mixture problems of all kinds. Write the two components of the mixture on the left. Here, they are 90 and 85. (I usually put the larger one on top.) Put the mixed value in the middle, and form differences along the lines of an X, as shown. The numbers on the right give the relative contributions of the constituents at the same level in the diagram. Here, the ratio of X to Y is shown as 2 to 3.
For some mixture problems, you need to know the proportion of the constituent to the whole. In that case, add the ratio values to get the "whole". For example, here the X class students make up 2/(2+3) = 2/5 of the whole number of students.
For your problem, X/Y = 2/3, corresponding to selection D.
The <em><u>correct answer</u></em> is:
x³+x²+x+1.
Explanation:
First we write the polynomial out with all of the other powers of x, using 0 as their coefficients:
(1x⁴+0x³+0x²+0x-1)÷(x-1)
To perform synthetic division, we write the coefficients of the dividend in a row:
1 0 0 0 1
We take the 1 from x-1 and use it in the box. We then drop the first 1 from the row of coefficients down.
We multiply our 1 in the box by the 1 at the bottom; this is 1 and goes under the first 0 to the right of the 1 in the coefficients row. We now add this 0+1; this is 1 and goes at the bottom beside the other 1.
Multiply this by 1; this is 1 and goes under the second 0 from the left in the row of coefficients. Add this to the 0; this is 1 and goes at the bottom, to the right of the other two 1's.
Multiply this by 1; this is 1 and goes under the third and last 0 in the row of coefficients. Add this to the 0; this is 1 and goes at the bottom, to the right of the other three 1's.
Multiply this by 1; this is 1 and goes under the -1 in the row of coefficients. Add this to the -1; this is 0 and goes at the bottom, to the right of the four 1's. This 0 means there is no remainder and the quotient was evenly divided. It gives us
1 1 1 1 0
This means we have 1x³+1x²+1x+1 with no remainder.